Symfony查问体例实例小结

本文实例报告了Symfony查问体例。分享给大师供大师参考，详细以下：

1. createQuery的写法

$sql = "SELECT COUNT(DISTINCT(g.goodsId)) FROM AppBundle:GoodsIndex g WHERE g.status = :status";
$params = array(
 "status" => GoodsIndex::STATUS_NORMAL,
);
if (!empty($keywords)) {
 $params["keywords"] = "%{$keywords}%";
 $sql .= " AND g.keywords like :keywords ";
}
 if (!empty($warehouseIdList)) {
  $params["warehouseIdList"] = $warehouseIdList;
  $sql .= " AND g.warehouseId IN :(warehouseIdList)";
 }
$goodsNum = $this->entityManager->createQuery($sql)->setParameters($params)->getSingleScalarResult();

小我总结：:是指占位符的意义，避免sql注入。以是把一切须要的参数做成数组$params外面。

2. getQuery的写法

$orderBy = "p.".$searchOptions["orderBy"];
$repository = $this->entityManager
 ->getRepository("AppBundle:GoodsIndex");
$query = $repository->createQueryBuilder("p");
$query->select("DISTINCT(p.goodsId)");
$query->where("p.keywords like :keywords")
 ->setParameter("keywords", "%{$searchOptions["keywords"]}%")
 ->andwhere("p.status = :status")
 ->setParameter("status", GoodsIndex::STATUS_NORMAL)
 ->orderBy($orderBy, $searchOptions["order"])
 ->setFirstResult($pagination["pageSize"] * ($pagination["page"] - 1))
 ->setMaxResults($pagination["pageSize"]);
if (!empty($searchOptions["warehouseIdList"])) {
 $query->andWhere($query->expr()->in("p.warehouseId", $searchOptions["warehouseIdList"]));
}
$goodsIndexList = $query->getQuery()->getResult();

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但愿本文所述对大师基于Symfony2框架的PHP法式设想有所赞助。